Question

13. If A + B = 90, then find the value of SinA CosA
CosB SinB​

Answer 1

Step-by-step explanation:

Given:-

A+B=90

Find:-

sinAcosA=?

cosBsinB=?

solution:-

we know that

sin(A+B)=SinAcosB+cosAsinB

sin90=sinAcos(90-A)+cosAsin(90-A)

1=sinAsinA+cosAcosA

1=sin^2A+cos^2A