Question

13. If A, B, C are three collinear points A (3,4) and AC = 10 units then
C(x,y)-

Answer 1

Step-by-step explanation:

AB=

[(7−3)

2

+(7−4)

2

]

=

[16+9]

=

25

=5 units

But,

AC=AB+BC⇒BC=AC−AB

BC=10−5=5 units

Therefore B is the midpoint of AC.

Using section formula,

B(7,7)=[(x+3)/2],[(y+4)/2]

i.e., (x+3)/2=7 implies x=11

and (y+4)/2=7 implies y=10

therefore C=(11,10)