Physics, asked by mitalik0811, 19 days ago

13. If an electron is in the ground state of the hydrogen atom, the probability that its distance from the proton is more than one Bohr radius is approximately.

Answers

Answered by kiratikaravi
0

Answer:

15.a

Explanation:

The radial probability function for the ground state of hydrogen is

P(r)=(4r

2

/a

3

)e

−2r/a

where a is the Bohr radius.

The integral table of Appendix E may be used to evaluate the integral r

avg

=∫

0

rP(r)dr.

Setting n=3 and

replacing a in the given formula

with 2/a (and x with r), we obtain

r

avg

=∫

0

rP(r)dr=

a

3

4

0

r

3

e

−2r/a

dr

=

a

3

4

(2/a)

4

6

=1.5a

Similar questions