Question

13) If diameter of wire as measured by screw
gauge are 0.202 cm, 0.208 cm, 0.205 cm,
0.210 cm, 0.204 cm then relative error in
measurement is :
A) 0.206 B) 0.202 C) 0.0026 D) 0.0126​

Answer 1

Answer:

As i think answer is 'A'.

Answer 2

Explanation:

Am =0.202 +0.208+0.205+0.210.0.204÷5

1.029÷5

0.2058 round off. 0.206cm ...............1

absolute error =|0.206 -0.202| = 0.004. |0.206-0.208|=0.002

do samelike this .........then

absolute mean error =0.004+0.002+0.001+0.004+0.002÷5

0.013÷5

=0.0026............2

relative error= absolute mean error/ mean

so our mean is 0.206 cm .....from 1

0.0026÷0.206=0.0126........from 3

so ........

OPTION D IS CORRRCT

GUYS HAVE TO TELL U .....THIS ANS IS GIVEN BY A BRILLIANT

SO IT IS TOTALLY CORRCT