13. If one of the angles of a triangle is 130°, then the angle between the bisectors of
other two angles will be
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Consider a △ABC,such that ∠BAC=130∘ and bisectors of ∠B and ∠C meet at O.
To find: ∠BOC
Now, in △ABC,
∠BAC+∠ABC+∠ACB=180
130+∠ABC+∠ACB=180 (Angle sum property)
∠ABC+∠ACB=50
21(∠ABC+∠ACB)=25
∠OBC+∠OCB=25 (OB and OC bisect ∠ABC and ∠ACB)
Now, in △OBC,
∠OBC+∠OCB+∠BOC=180
25+∠BOC=180
∠BOC=155∘.
Answered by
1
Answer:
50° and 25° each..........
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