Question

13. If root3 sin a = cos a, find the value of (3cos^2o+2coso )/ (3cos0+2).​

Answer 1

Answer:

Step-by-step explanation:

√3sinΦ = cosΦ

sinΦ/cosΦ = 1/√3

tanΦ = tan30°

Φ = 30°

(3cos^2Φ + 2cosΦ)/3cosΦ+2

[3cos^2(30°) + 2cos(30°)] / 3cosΦ+2

[3×(√3/2)^2 + 2×(√3/2) ] / 3×(√3/2)+2

[9/4 + √3]/[3√3/2+2]

= (9+4√3)/(8+6√3)

Hope this helps you