Question

13. If secQ + tanQ +1=0 then (secQ - tanQ ) = ?
(a) 1 (b)-1 (c) o (d) 2​

Answer 1

if sec q + tan q = 1 then simple

sec q - tan q = - 1 by its reciprocal

Answer 2

Answer:

Since,

1+ tan²θ = sec²θ

=> sec²θ - tan²θ = 1

=> (secθ + tanθ)(secθ - tanθ) = 1

=> secθ - tanθ = 1/(secθ + tanθ)

Now, coming to the question,

secQ + tanQ + 1 = 0 (given)

=> secQ + tanQ = -1

=> secQ - tanQ = 1/(secQ + tanQ)

=> secQ - tanQ = 1/-1

=> secQ - tanQ = -1

Option (b) -1