Question

13. If the coercivity of Fe is 2000 A/m, then magnetic
field required is
(1) 4pie* 10-7 T
(2) 8pie * 10-41
(3) 8pie* 10-7T
(4) 4pie x 10-4T​

Answer 1

Answer:8π×10-4 T

Explanation:

A❤️

Answer 2

The magnetic field is $8\pi\times10^{-4}\ T$

(2) is correct option.

Explanation:

Given that,

Coerciivity of Fe = 2000 A/m

We need to calculate the magnetic field

Using formula of Coercivity

$Coercivity = \dfrac{B}{\mu_{0}}$

$B=Coercivity\times\mu_{0}$

Where, B = magnetic field

$\mu_{0}$ = permeability constant

Put the value into the formula

$B=2000\times4\pi\times10^{-7}\ T$

$B=0.0008\pi\ T$

$B=8\pi\times10^{-4}\ T$

Hence, The magnetic field is $8\pi\times10^{-4}\ T$

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Topic : magnetic field

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