13. If the point (2k – 3, k + 2) lies on the graph of the equation 2x + 3y + 15 = 0, find the value of ‘k’.
Answers
Answered by
1
Answer:
-15/7
Step-by-step explanation:
Hope it helps
Please mark as brainliest
Attachments:
Answered by
1
Answer:
Step-by-step explanation:
Given equation = 2x + 3y + 15 = 0
Given points = (2k – 3, k + 2)
We consider 2k - 3 as x and k +2 as y
So put these values in the equation.
That is,
=> 2(2k-3) + 3(k+2) + 15 =0
=> 4k-6 + 3k + 6 +15 =0
Now put the like terms together..That is
=> 4k + 3k + 6 + 15 - 6 = 0
=> 7k + 15 = 0
=> 7k = 0 - 15
=> 7k = - 15
=> k = -15/7
So i hope this helps you....
Plz mark me the brainliest...
Similar questions