Question

13. If x = -2/3 and y 1/4 Find (x+y) (x-y)​

Answer 1

Answer:

$(x + y) \: (x - y)$

${x}^{2} - {y}^{2}$

$x = \frac{ - 2}{3} \: and \: y = \frac{1}{4}$

${ (\frac{ - 2}{3} )}^{2} - ( { \frac{1}{4} })^{2}$

$\frac{4}{9} - \frac{1}{16}$

$\frac{64 - 16}{144} = \frac{48}{144} = \frac{1}{3}$

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