Question

13.If x = 2 sec?0 and y = 2tan0 - 1, then find x - y.​

Answer 1

Answer:

if question is 2sec^2-2tan^2

then 2(sec^2- tan^2)

2×1=2

and if question is 2sec - 2 tan

then 2(sec-tan)

2(1/cos-sin/cos)

2(1-sin/cos)