Question

13. if(x- y) = 6 and xy = 1, then the value of x³-y³
A. 324
B. 234
C. 322
D.432
explain it ​

Answer 1

Answer:

B. 234

Step-by-step explanation:

here,

x-y = 6

xy=1

to find the value of x^3-y^3

now,

according to question,

x^3-y^3= (x-y)^3 + 3xy (x-y)

=(6)^3 +3*1*6

=216+18

=234