Question

13. If x+y+z=0, show that x + y +z = 3xyz.​

Answer 1

Answer:

we know that;

x3+ y3+z3-3xyz=(x+y+z)•(x2+y2+z2-xy-yz-zx)

when we put ,x+y+z= o in the rhs, then whole term in the rhs become zero.

thus,

x3+y3+z3 -3xyz=o

x3+y3+z3=3xyz.

I hope it would help you

thank you