Question

13.In 4ABC, D is the foot of the altitude from A on segment BC. If

AD = 24, AC = 30 and BC = 28. Find AB.​

Answer 1

Answer:

ab=26

Step-by-step explanation:

In △ADC, by Pyathagoras theorem

DC2 = AC2 − AD2 = 302 − 242 = 900 − 576 = 324 = 182

.

AD 4

∴ BD = BC − DC = 10.

In △ADB, we get by Pyathagoras theorem

AB2 = AD2 + DB2 = 242 + 102 = 676 = 262 ∴ AB = 26