Question

13. In ΔABC, BO is the bisector of angle B and CO is the bisector of angle C. If
angle ABC = 62° and angle ACB = 48°, find angle BOC.




with solution
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Answer 1

Answer:

115⁰

Step-by-step explanation:

ABC = 62⁰

and ACB = 48⁰

OBC = ABC/2 = 62/2 = 31⁰

OCB = ACB/2 = 48/2 = 24⁰

BOC + OBC + OCB = 180⁰

BOC + 31⁰ + 24⁰ = 180⁰

BOC = 180⁰ - 31⁰ - 24⁰ = 180⁰ - 65⁰ = 115⁰