Question

13.
In an increasing sequence of 10 consecutive
integers, the sum of the first 5 integers in 560.
The sum of the last 5 integers in the sequence is:
a. 250
b. 558
c. 855
d. 585​

Answer 1

Answer:

d. 585

Step-by-step explanation:

Let ten consecutive integers are x, x+1 , x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9 .

sum of first five consecutive integers is 560 .

x+ x+1+ x+2+ x+3+ x+4 = 560

5x+10 = 560

5x = 560-10

5x = 550

x = 550/5

x = 110

So,

sum of last five consecutive integers is

x+5+ x+6+ x+7+ x+8+ x+9 = 5x + 35

= 5× 110 +35

= 550+35

= 585

Answer 2

Answer:

Say our 10 consecutive integers are x, x+1, x+2, ..., x+9.

.

Notice that the 6th term is 5 more than the 1st term, the 7th term is 5 more than the 2nd term, ..., the 10th term is 5 more than the 5th term, thus the sum of the last 5 terms is 5*5=25 greater than the sum of the first 5 terms. Therefore the answer is .so the answer is d. 585

OR:

.

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