Question

13
In Dumta's method 0.52g of an organic compound. On combustion gave
68.6 ml N, a 27'c and 756 mm pressure. What is the percentage of
nitrogen in the compound,​

Answer 1

Answer:

Organic compound DumasMethod→N2+ other product

volume of N2.V=68.6ml

pressure P=76mmHg=1atm 

Temprature T=273+27=300k

n=RTPv=0.0821×3001×68.6×10−3=2.785×10−2

amount of nitrogen 2.785×10−2×28=0.078

% of nitrogen =0.520.078=14.93%