13. In each of the following figures, one side of a triangle has been produced. Find all the angles of the triangles in each case
Answers
Step-by-step explanation:
QUESTION
In each of the following figures, one side of a triangle has been produced. Find all the angles of the triangles in each case
FIRST QUESTION
BCA = 180-125
BCA =55
SECOND QUESTION
ABC= 180-120
60
A+B+C=180
2x+x+60=180
3x=180-60
3x=120
x=40
A= 2X40
80
C=40
THIRD QUESTION
BAC = 180 -80= 100
BAC = 180 -80= 100A+B+C = 180
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =180
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-100
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80X= 16
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80X= 16B = 2X16
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80X= 16B = 2X1632
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80X= 16B = 2X1632C= 3X16
BAC = 180 -80= 100A+B+C = 1803x+2x+100 =1805x = 180-1005x = 80X= 16B = 2X1632C= 3X1648
FOURTH QUESTION
CBA= 180-140
Y=40
BAC=180-130
Z=50
A+B+C=180
X+Y+Z=180
x+40+50=180
x+90=180
x=180-90
x=90
FIFTH QUESTION
BCA=180-125
Y=55
A+B+C=180
x+y+55=180
x+55+55=180
x+110=180
x=180-110
x=70
SIXTH QUESTION
ABC=180+130
50
A+B+C=180
x+x+50=180
2x=180-50
x=130/2
x=65
A=65
C=65
Step-by-step explanation:
fourth:
x+y=130°,
y=180-140=40°
=> x=130-40=90°
z=180°-130°=50°