Question

13. In each of the following numbers, replace M by the smallest whole number to make the
resulting number divisible by 11.
(i) 39 M 2
(ii) 3 M 422
(iii) 70975 M. (iv) 14 M 75​

Answer 1

Answer:

7matfdrgfrwzurdqhsggs

Answer 2

Answer:

(i) 39 M 2 The given number = 39 M 2 Sum of its digits in odd places = 3 + M Sum of its digits in even place = 9 + 2 = 11 Their Difference = 11 – (3 + M) 11 – (3 + M) = 0  11 – 3 = M  M = 8 (ii) 3 M 422 The given number = 3 M 422 Sum of its digits in odd places = 3 + 4 + 2 = 9 Sum of its digit in even places = M + 2 Difference of the two sums = 9 – (M + 2) 9 – (M + 2) = 0 9 – 2 = M M = 7 (iii) 70975 M The given number = 70975 M Sum of its digits in odd places = 0 + 7 + M = 7 + M Sum of its digit in even places = 5 + 9 + 7 = 21 Difference of the two sums = 21 – (7 + M) => 21 – (7 + M) = 0 => 21 = 7 + M => M = 14 Since, M cannot be two digit number M = 14 – 11 = 3 (iv) 14 M 75 The given number = 14 M 75 Sum of its digit in odd places = 1 + M + 5 = M + 6 Sum of its digit in even places = 4 + 7 = 11 11 – (M + 16) = 0 11 = M + 6 11 – 6 = M M = 5