Math, asked by prachiparmar19, 1 month ago

13. In Fig. 11.43, if EC || AB, angle ECD = 70° and angle BDO = 20°, then angle OBD is
Please give answer in step-by-step ​

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Answers

Answered by sdp3076
2

Answer:

Step-by-step explanation:

as EC║AB,considering cd as the transversal,

∠ECD and ∠AOD are corresponding angles

we know that corresponding angles are equal so ∠ECD=∠AOD=70°

now,∠AOD and ∠BOD  are linear.so ∠BOD=180-∠AOD=180-70=110°

NOW WE HAVE ALMOST REACHED THE ANSWER

we know that the sum of the interior angles of a triangle is 180°.

so in triangle BOD, ∠OBD+∠ODB+∠BOD=180°⇒∠OBD+20+110=180°

∠OBD+130=180⇒∠OBD=180-130=50°

SO ∠OBD=50°

THANK YOU

Answered by purushothamvajjula
0

Answer:

Step-by-step explanation: as EC║AB,considering cd as the transversal,

∠ECD and ∠AOD are corresponding angles

we know that corresponding angles are equal so ∠ECD=∠AOD=70°

now,∠AOD and ∠BOD  are linear.so ∠BOD=180-∠AOD=180-70=110°

NOW WE HAVE ALMOST REACHED THE ANSWER

we know that the sum of the interior angles of a triangle is 180°.

so in triangle BOD, ∠OBD+∠ODB+∠BOD=180°⇒∠OBD+20+110=180°

∠OBD+130=180⇒∠OBD=180-130=50°

SO ∠OBD=50°

THANK YOU

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