13. In Fig. 11.43, if EC || AB, angle ECD = 70° and angle BDO = 20°, then angle OBD is
Please give answer in step-by-step
Answers
Answer:
Step-by-step explanation:
as EC║AB,considering cd as the transversal,
∠ECD and ∠AOD are corresponding angles
we know that corresponding angles are equal so ∠ECD=∠AOD=70°
now,∠AOD and ∠BOD are linear.so ∠BOD=180-∠AOD=180-70=110°
NOW WE HAVE ALMOST REACHED THE ANSWER
we know that the sum of the interior angles of a triangle is 180°.
so in triangle BOD, ∠OBD+∠ODB+∠BOD=180°⇒∠OBD+20+110=180°
∠OBD+130=180⇒∠OBD=180-130=50°
SO ∠OBD=50°
THANK YOU
Answer:
Step-by-step explanation: as EC║AB,considering cd as the transversal,
∠ECD and ∠AOD are corresponding angles
we know that corresponding angles are equal so ∠ECD=∠AOD=70°
now,∠AOD and ∠BOD are linear.so ∠BOD=180-∠AOD=180-70=110°
NOW WE HAVE ALMOST REACHED THE ANSWER
we know that the sum of the interior angles of a triangle is 180°.
so in triangle BOD, ∠OBD+∠ODB+∠BOD=180°⇒∠OBD+20+110=180°
∠OBD+130=180⇒∠OBD=180-130=50°
SO ∠OBD=50°
THANK YOU