Question

13. In Figure 9. ABCD is a rhombus in which <ABD = 40°
Find i) <BAC
ii)<BCD
iii)<ADC
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Answer 1

Answer:

1)In ∆AOB=180(Sum of triangle)

A+O+B=180

X+40+X=180

2x=180-40

2x=140

x=140÷2

x=70

A=70, B=70

ii)In ∆ BCD

B+C+D=180

70+x+x=180

2x=180-70

2x=110

x=55

Hence D=55, C=55

iii)We already find angle D