13. In ∆PQR, LQ = 90°,PQ = 20cm and QR = 21cm. Find the perimeter of ∆PQR.
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Step-by-step explanation:
Given : In ∆PQR , LQ = 90°
PQ= 20 cm
QR = 21 cm
PR = ?
By Pythagoras theorem ,
H²= P² + B²
PR² = PQ² + QR²
PR² = (20)² + (21)²
PR² = 400 + 441
PR² = 841
PR = √841
PR = 29 cm
Perimeter of ∆ PQR
= PR + PQ + QR
= 29 + 20 +21
= 70 cm
Hence, the Perimeter of ∆PQR is 70 cm
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