Question

13.
In the adjoining figure 1m and t is the transversal then x =
(8x+10)
m
(6x+20)
OR​

Answer 1

Answer:

∠1+∠2=180

∘

(Adjacent angle on straight line are supplementary)

⇒50

∘

+∠2=180

∘

⇒∠2=180

∘

−50

∘

⇒∠2=30

∘

Now l∣∣m and t is transversal

∴∠x=∠2 (Alternate angles)

⇒∠x=130

∘