13. In the following figure, AC || BD, LCAF
= 25°, LDBG = 65° and BF=BA. Then,
LBFE is equal to
25°
16 in
65°
A
B
G
a) 90°
c) 140°
b) 1550
d) 1650
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given ,. ∠CAE = 25° & ∠GBD =65°
since , AC II BD
∠BAC = ∠GBD ( corresponding angles )
∠BAC = ∠GBD = 65°
∠BAC = ∠CAE + ∠BAE = 65°
∠BAC = 25° + ∠BAE = 65°
∠BAE = ∠BAF = 65° - 25°
∠BAF = 40°
it's also given that, BF = BA
then , ∠BAF = ∠AFB = 40°
( angles opposite to equal sides are equal )
∠BFE + ∠AFB = 180° ( angles on straight line )
∠BFE = 180° - ∠AFB
∠BFE = 180° - 40°
∠BFE = 140°. ( option C )
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