Question

13. In the given figure, ABCE is a parallelogram
P is the midpoint of AD and AD IEC
If AD = 20 cm and EC = 18 cm, then find
the area of the given figure.
C
(A) 300 cm
(B) 280 cm
(C) 270 cm
(D) 290 cm​

Answer 1

Answer:

c) 270 cm

Step-by-step explanation:

P is the midpoint of AD and AD = 20cm.

since P is the midpoint

AP = DP

therefore half of AD = 10 cm ----(1)

Half of AD = AP --- (2)

FROM (1) AND (2)

AP = 10 cm

AP is also the height of the ||gm ABCE.

EC is the base of ||gm ABCE

and BC = 18 cm

we know that,

Area of ||gm = base × height

= 18cm × 10 cm

= 180 cm square

Now in ∆EDC,

PD is the height and EC is the base.

PD = 10cm { P is the midpoint of AD }

EC = 18 cm { Given }

we know that,

area of a triangle = 1/2 × base × height

= 1/2 × 18cm × 10 cm

= 90 cm square

Now,

if we add the area of the ||gm ABCE and ∆EDC we will get the area of the whole figure.

So, Area of ||gm + Area of ∆

= 180 cm square + 90 cm square

= 270 cm square

Therefore the answer is 270 cm square.

HOPE IT HELPED YOU IF YES THEN MARK ME THE BRAINLIEST.

Answer 2

Answer:

c) 270 cm

Step-by-step explanation:

P is the midpoint of AD and AD = 20cm.

since P is the midpoint

AP = DP

therefore half of AD = 10 cm ----(1)

Half of AD = AP --- (2)

FROM (1) AND (2)

AP = 10 cm

AP is also the height of the ||gm ABCE.

EC is the base of ||gm ABCE

and BC = 18 cm

we know that,

Area of ||gm = base × height

= 18cm × 10 cm

= 180 cm square

Now in ∆EDC,

PD is the height and EC is the base.

PD = 10cm { P is the midpoint of AD }

EC = 18 cm { Given }

we know that,

area of a triangle = 1/2 × base × height

= 1/2 × 18cm × 10 cm

= 90 cm square

Now,

if we add the area of the ||gm ABCE and ∆EDC we will get the area of the whole figure.

So, Area of ||gm + Area of ∆

= 180 cm square + 90 cm square

= 270 cm square

Therefore the answer is 270 cm square.

HOPE IT HELPED YOU IF YES THEN MARK ME THE BRAINLIEST.