13. In the given figure, AD = BD = BC and angleABD = 38°, compute the measures of x, y and z.
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In the given figure, if ∠ADE=∠B, show that ΔADE∼ΔABC. If AD=3.8cm,AE=3.6cm,BE=2.1cm and BC=4.2cm, find DE.
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from triangle ABD
Given AD=BD
then <ABD=<BAD
so,ABD+BAD+ADB=180
38+38+ADB=180
ADB=104
From triangle BDC
BC=BD,<BDC=<DCB
so,DBC+BDC+DCB=180
y+z+DCB=180
y+2z=180
from figure y=104
104+2z=180
2z=76
z=38
Therefore x=38,y=104,z=38
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