Question

13. In the given figure, find the value of x. R 100° S 120° Q 80° Px°

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Answer 1

$\huge{\bf{\purple{\underline{\underline{\colorbox{lavender}{\color{purple}{ᎪղՏωᎬя᭄}}}}}}}$

please attach the figure also but let take an example

∠TQS=180−∠PQT−∠SQR \\ =180–70–50=60

WKT OQ⊥PR

∠OQS=90−∠SQR=90–50=40

In △OQS

∠OQA=∠OSQ=40

∠QOS=180−∠OQS−∠OSQ=180–40–40=100

Now,

∠QTS= $\frac{1}{2}$

∠QOS because angle made but n arc at the center is twice the angle made by the arc on any point of circle

$∠QTS= \frac{100}{2}$

=50

In △QTS

∠TSQ=180–50−60=70

∠TSO+∠OSQ=70

x=70–40=30∘

Hope it's helpful↑(◍•ᴗ•◍)❤࿐

Answer 2

Answer:

In △QTS

∠TSQ=180–50−60=70

∠TSO+∠OSQ=70

x=70–40=30∘

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