Question

13. *In triangle ABC,
$ab = 6 \sqrt{3} cm \: ac = 12cm \: and \: bc = 6cm.then \: angle \: b =$
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Answer 1

Answer:

90°

Step-by-step explanation:

AB² = (6√3)² = 36×3 = 108 cm.

AC² = 12² = 144 cm.

BC² = 6² = 36 cm.

Here, AB²+BC²=AC²

This satisfied the Pythagoras theorem.

Therefore, Angle B = 90°.

Hope it helps..

Thank you!!