Question

13. Is (x+2) a factor of x3
- x2 - 10x -8?​

Answer 1

Answer:

Yes.

Step-by-step explanation:

If (x+2) is a factor of x³ - x² - 10x - 8, then p(-2) = 0.

=> p(-2) = (-2)³ - (-2)² - [10(-2)] - 8

=> p(-2) = -8 - 4 + 20 - 8

=> p(-2) = 20-20

= 0.