13 no. plz help fast . tomorrow is my exam
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Hi mate!!
Q.1
Angle (NOM) + Angle (OMP) + Angle (MPN) + Angle (PNO)=360. because sum of angles of a four sideded fig is always = 360.
Angle (NOM) =35°. ,. Angle (OMP)= 90°. ,. Angle ( MPN)=? and Angle (PNO)= 90°
So,
Angle (MPN) = 360° - 215°
Angle (MPN)= 145°
!!!!!!!! Hope it helps!!!!!
Q.1
Angle (NOM) + Angle (OMP) + Angle (MPN) + Angle (PNO)=360. because sum of angles of a four sideded fig is always = 360.
Angle (NOM) =35°. ,. Angle (OMP)= 90°. ,. Angle ( MPN)=? and Angle (PNO)= 90°
So,
Angle (MPN) = 360° - 215°
Angle (MPN)= 145°
!!!!!!!! Hope it helps!!!!!
anshbansal07688:
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Answered by
0
angle NPM+ANGLE PMO+ANGLE MON+ANGLE NPM= 360° (ANGLE SUM PROPERTY OF QUADRILATERAL)
90+90+35+NPM=360
215+NPM=360
NPM=360-215
NPM=145
90+90+35+NPM=360
215+NPM=360
NPM=360-215
NPM=145
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