Question

13. Perimeter of a rectangle whose length (1) is 4 cm more than twice its breadth (b) is 14 cm. The pair of linear equations representing the above information is 1+ 4 = 2b 1-b=4 a) 2/1 + b) = 14 202 = 2(1 + b) = 14 12b + 4 2= 2b + 4 (c) 1 + b = 14 美 2(1 + b) = 14 (b) (d)​

Answer 1

Answer:

Let the length be l and breadth be b.

According to question,

l = 4 + 2b. ....(I)

perimeter = 14

2 × (Length + Breadth) = Perimeter

=> 2 × (l + b) = 14

=> 2 × { (4 + 2b) + b } = 14 (from (I))

=> 2 × { 4 + 3b } = 14

=> 8 + 6b = 14

=> 6b = 14 - 8

=> b = 6 ÷ 6

=> b = 1

From (I),

l = 4 + 2 × 1

= 4 + 2

= 6

Length = 6 cm

Breadth = 1 cm