Question

13. Prashant Shoes Shop was placing an order for making cardboard boxes for packing their
shoes. Two sizes of boxes were required. The bigger of dimensions 20 cm x 15 cm x 5 cm and
the smaller of dimensions 15 cm x 10 cm x 5 cm. For all the overlaps, 2% of the total surface
area is required extra. If the cost of the cardboard is *5 for 1000 cm²?, find the cost of cardboard
required for supplying 200 boxes of each kind.​

Answer 1

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✩☞ the cost of cardboard required for supplying 200 boxes of each kind is : Rs. 1530✔

__________________________________

$\Large\bf\underline{\red{E}\green{X}\orange{P}\pink{L}\red{A}\purple{N}\orange{A}\blue{T}\red{I}\purple{O}N}$

${ \fbox {\red{For \: bigger \: box :}}}$

$\underline \mathbf{ \purple{Given: }}$

Length (l) = 20 cm,

Breadth (b) = 15 cm,

Height (h) = 5 cm

Now,

✩☞ Total surface area of a box = 2(lb + bh + hl)

= 2[(20 x 15) + (15 x 5) + (5 x 20)] cm2

= 2 [300 + 75 + 100] cm2

= 2[475] cm2

= 950 cm2

Therefore,

total surface area of 200 boxes = (200 x 950) cm2  = 190000 cm2

$\fbox \red{For smaller box:}$

$\underline \mathbf{ \purple{Given: }}$

Length (l) = 15 cm,

Breadth (b) = 10 cm,

Height (h) = 5 cm

✩☞ Total surface area of a box = 2 [lb + bh + hl]

= 2[(15 x 10) + (10 x 5) + (5 x 15)] cm2

= 2[150 + 50 + 75] cm2 

= 2[275] cm2 = 550 cm2

∴ Total surface area of 200 boxes = (200 x 550) cm2 = 110000 cm2

Now,

total surface area of both type of boxes

= 190000 cm2 +110000 cm2

 = 300000 cm2

⟹ Area for overlaps = 2% of [total surface area]

= (2/100) x 300000 cm2 

= 6000 cm2

∴ Total surface area of the cardboard required = [Total surface area of 200 boxes of each type] + [Area for overlaps]

= 300000 cm2 + 6000 cm2 

= 306000 cm2

∵ Cost of 1000 cm2 cardboard = Rs. 5

∴ Cost of 306000 cm2 cardboard

= Rs.(5×306000)/1000 = Rs. 1530

[Note: cm2 ⟹ cm^2 or cm square units.]

★━━━✩━━★♥️♥️★━━✩━━━★

☘彡✩Thank You For Asking✩彡☘

↬↬↬ $\large{\fcolorbox{grey}{yellow}{Hope \ it \ helps}}$

Answer 2

Answer:

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