Question

13 Prove that (cxa) x(axb) = (abc) a
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Answer 1

Answer:

[axb bxc cxa] is nothing but a box of [a b c]

[axb bxc cxa] = (axb).((bxc)x(cxa))

which is a quadrapule product of four vetors

we have a formula for quadrapule product that is

(axb)x(cxd) = [a b d]c - [a b c]d

therefore applying this formula

(axb).((bxc)x(cxa)) = (axb).([b c a]c - [b c c]a)

[b c c] = 0 because when 2 vectors are equal out of three then the box of those 3 vectors will be 0

therefore

=(axb).([b c a]c) = ((axb).c)[b c a]

= [a b c][b c a]

box product follows commutative rule therefore [b c a] = [a b c] = [c a b]

=[a b c][a b c]

=[a b c]^2

hence proved :)

Answer 2

Step-by-step explanation:

13 Prove that (cxa) x(axb) = (abc) a