Math, asked by maliklokender38, 9 months ago

13. Rene is 6 years older than her younger sister. After 10 years, the sum of their ages
ill be 50 years. Find their present ages?
Find the number?​

Answers

Answered by kotaravi54321
0

Answer:

Rene at present is 18 years old and her younger sister is 12 years old. Thus after 10 years, Rene will be 28 years old and her younger sister will be 22 years old and thus total of their ages would be 50.

Answered by ramvishal048
1

Answer:

present age of rene is 15 years and her younger sister is 9 years.

Step-by-step explanation

Let the present age of Rene be y and her younger sister be x

So age of Rene,

y = x+6

y-x =6   ..............(1)

After 10 years,

Age of Rene

y+10 + x+6+10 = 50 years  

y+x = 50 -26

y+ x = 24 ..........(2)

on adding equation (1) and (2)

y-x = 6

y+x + 24

2y  =30

y=30

   2

y= 15 years

and from eq. (2)

y+x =24

15+x= 24

x= 24-15

x= 9 Years

Similar questions