Question

13 sin A = 5 and A is an acute then find the value of 5sin A -2cos A divide by tan A

Answer 1

Answer:

12/65

Step-by-step explanation:

HEY there, see it is given that 13 sin A= 5 and it is a acute angle so we can say that the sides must be 12, 13, and 5( ∵pythagoran triplet)

SO, now sin A=5/13, cos A= 12/13 and tan A= 5/12

⇒{(5×5/13)-(2×12/13)}÷5/12

⇒(1/13)×12/5

⇒12/65

hope it helps

Answer 2

Answer :-

13 sinA = 5

sinA = 5/13 = p/h

Here,

• perpendicular = 5
• hypotenuse = 13

Base = √ h² - p²

→ √ (13)² - (5)²

→ √ 169 - 25

→ √144

→ 12 units

cosA = b/h = 12/13

tanA = p/b = 5/12

• 5sinA - 2cosA/tanA

→ 5 (5/13) - 2(144/65)

→ 25/13 - 288/65

→ (125 - 288)/65

→ -163/65