13 sin A=5, evaluate: 5sinA - 2cos A / tan A
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since 13 sin A = 5
Therefore sin A = 5/13
now evaluating 5sinA-2cosA/tanA
5×5/13 - 2×12/13 /5/12
25/13 - 24/13 / 5/12
1/13 / 5/12
12/65
Therefore sin A = 5/13
now evaluating 5sinA-2cosA/tanA
5×5/13 - 2×12/13 /5/12
25/13 - 24/13 / 5/12
1/13 / 5/12
12/65
sweet2145:
Thank you sir
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