Question

13. Solve,
[X+1 2 3 ]
[1 X+2 3 ]=0
[1 2 X+3 ]​

Answer 1

Answer:

i) (x + 1)2 = 2(x – 3). ( ii) x2 ... x3 – 4x2 – x – 1 – x3 + 6x2 – 12x + 8 = 0.