Question

13
Starting from rest, a cyclist attains a velocity of 60 ms-1 in 300seconds. If he applies
slows down to rest at the rate of 2ms 2. Find
i. The acceleration in first 200 seconds.
ii. The time taken to come to rest in deceleration.
ii. The displacement in the whole journey.​

Answer 1

Answer:

i) u=0. v=60. t=300sec

v=u+at

60 = a×300

a= 0.2m/ s

ii)u= 60. v=0. a=-2

v= u- at

0=60-2t

t= 30 sec.

Answer 2

Answer:

i) u=0. v=60. t=300sec

v=u+at

60 = a×300

a= 0.2m/ s

ii)u= 60. v=0. a=-2

v= u- at

0=60-2t

t= 30 sec.

Explanation: