Question

13. Ten men, working for 6 days of 10 hours each ,finish 5/21 of a piece of work.How many men working
at the same rate and for the same
number of hours each day, will be required to
complete the remaining work in 8 days?​

Answer 1

Answer:

24

Step-by-step explanation:

10 men after working for 6*10 = 60 hours each finished 5/21 of the work.

Let contribution by each man be $\frac1x$

$\dfrac1x \times 10 \times 60 = \dfrac{5}{21}$

$\dfrac1x = \dfrac{5}{21 \times 600}$

Remaining work = 1 - 5/21 = 16/21

Let the number of men required = M

Number of hours worked = 8*10 = 80 hours

$\dfrac1x \times M \times 80 = \dfrac{16}{21}$

$M = \dfrac{16}{21 \times 80} \times \dfrac{21 \times 600}{5}$

$M = 24$