Question

13. Ten men, working for 6 days of 10 hours each,
or
finish of a piece of work. How many men
21
working at the same rate and for the same
number of hours each day, will be required to
complete the remaining work in 8 days?​

Answer 1

1 day working of 10 men = (5/21)×(1/6)

1 day working of 1 man =(5/21) ×(1/6)×(1/10)

8 day working of 1 men =(5/21)×(1/6)×(1/10)×8

= 2/63

remaining work = 1-(5/21) = 16/21

hence, number of men required to complete the work in 8 days = (16/21)÷(2/63)

=(16×63)/(2×21) = 8×3 = 24 men

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I hope this helps.

Answer 2

Answer:

Step-by-step explanation:

Work do one = 5/21

Remaining work = 1- (5/2) = 16/21

5/21 of a work can be done in 6 days working

10 hours a day by = 10 m

1 work can be done in 6 days working 10 hours a day by = (10 × 21)/5

1 work can be done in 1 day working 10 hours day by = (10 × 21 × 6)/5 men

16/21 work can be done in 8 days working 10 hours a day by = (10 × 21 × 6 × 16)/(5 × 21 × 8) = 24 men