Math, asked by priyayadav002005, 11 months ago

13) The 17 term of an A.P. exceeds the 10th term by 7. Find the common difference.​

Answers

Answered by Dynamicsreborn
0

Answer:

here:

17th term = a+16d

and, 10th term = a+9d

A.T.Q.

a+16d= a+9d+7

7d=7

d=1 Hence the common difference is 1.

Answered by diyasikka
3

Answer:

Common difference is 1

Step-by-step explanation:

an=a+(n-1)d

  • a17=a+16d
  • a10=a +9d

Now,it is given that a17 exceeds

a10 by 7

So, a10+7=a17

On putting the value of a17 and a10..

a+9d+7=a+16d

a-a+7=16d-9d

7=7d

1=d

Hence,common difference is 1.

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