Question

13. The age of two number is 12. the digits are reversed, the new number is 4 by 7 times the original number. Find the number​

Answer 1

Answer:

Given sum of the digits is 12

Let the digits in ones place be x

Hence the digit in tens place is (12–x)

The original number =10(12–x)+x=120–9x

Number formed by reversing the digits =10x+(12–x)=9x+12

Given that number formed by reversing the digits is 54 greater than the original number.

⇒9x+12=(120–9x)+54=174–9x

⇒18x=174–12=162

∴x=9

The original number =120–9x=120–9×9=120−81=39

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Answer 2

Answer:

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ANSWER

Let the two digit number be 10x+y

Sum of digit : x+y=12 __(i)

A.t.Q : 2(10x+y)−(10y+x)=12

⇒20x+2y−10y−x=12

⇒19x−8y=12

⇒19x−8y−12=0 __(ii)

Put eq. (i) in eq. (ii)

⇒19(12−y)−8y−12=0

⇒228−19y−8y−12=0

⇒27y=216

⇒y=8

x+y=12

x=12−8

x=4

Number : 48