13. The area of a trapezium is 40 cm2. Its
parallel sides are 12 cm & 8 cm. What is the
distance between the parallel sides?
(1 Point)
2 cm
4 cm
6 cm
Answers
Answer:
The distance between the parallel sides of the trapezium is 4 cm.
Area of trapezium = 1/2 × 12 + 8 × distance between the two parallel sides
= 1/2 ×20 ×height
40 = 10h
h = 40 /10
h = 4 cm
Step-by-step explanation:
I hope it helps you
Given,
Area of a trapezium = 40 cm^2
Length of its longer parallel side = 12 cm
Length of its shorter parallel side = 8 cm
To find,
The distance between the parallel sides.
Solution,
We can simply solve this mathematical problem using the following process:
Let us assume that the distance between the parallel sides of the trapezium is x cm.
As per mensuration;
Area of a trapezium
= 1/2 × (sum of its parallel sides) × (distance between the parallel sides)
Now, according to the question;
Area of a trapezium = 40 cm^2
=> 1/2 × (sum of its parallel sides) × (distance between the parallel sides) = 40 cm^2
=> 1/2(12 cm + 8 cm) × x = 40 cm^2
=> 1/2(20 cm) × x = 40 cm^2
=> 10 cm × x = 40 cm^2
=> x = 4 cm
Hence, the distance between the parallel sides is equal to 4 centimeters.