13. The difference between two numbers is 26 and one number is three times the other.
14. The sum of the digits of a two-digit number is 9. Also, nine times this number is twice
the number obtained by reversing the order of the digits. Find the number
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13.
- let the number be x
- second number 3x
- 3x-x = 26
- 2x=26
- x=26/2
- x=13
14.
- Let the unit digit and tens digits of the number be x and y
- Number = 10y + x
- Number after reversing the digits = 10x + y
- ⇒ x + y = 9 ---- (i)
- ⇒ 9(10y + x) = 2(10x + y)
- ⇒ 88y - 11x = 0
- ⇒ -x + 8y =0 ---- (ii)
- Adding equation (i) and (ii), we get
- ⇒ 9y = 9
- ⇒ y = 1---- (iii)
- Putting the value in equation (i), we get
- ⇒ x = 8
- Hence, the number is 10y + x = 10 × 1 + 8 = 18.
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