Question

13. The difference between two positive numbers is 40 and the ratio of these integers is 1 : 3. Find the integers.

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Answer 1

Answer:

3x-x= 40

2x=40

x=40/2

x=20 and 3x=20×3 =60

Answer 2

Given :

• The Difference between two numbers is 40 .
• The ratio of these two numbers is 1:3 .

To Find :

• Find the Integers

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SolutioN :

$\dag$ Lett the Ratios :

• 1st Integer = 1y
• 2nd Integer = 3y

$\dag$ Calculating the Value of y :

${\longmapsto{\qquad{\sf{ \bigg\{ 2nd \; Integer \bigg\} - \bigg\{ 1st \; Integer \bigg\} = 40 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 3y - 1y = 40 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 2y = 40 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ y = \dfrac{40}{2} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ y = \cancel\dfrac{40}{2} }}}} \\ \\ \\ \ {\qquad \; \; {\longmapsto \; {\pmb{\underline{\boxed{\purple{\frak{ y = 20 }}}}}}}}$

$\dag$ Calculating the Integers :

• 1st Integer = 1y = 1(20) = 20
• 2nd Integer = 3y = 3(20) = 60

$\therefore \;$ The two Integers are 60 and 20 .

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