Question

13) The difference of ages between two sisters is 10 years. 15 years ago if the older one was

twice as old as the younger one, find their present ages.​

Answer 1

AnSwEr

Let elder sisters age be X years

So, younger sister age will be x - 10 years

If 15 years ago elder sister was = x-15

And younger sister was = x-10-15 = x- 25

x-15 = 2(x-25)

x-15 = 2x-50

X = 35

Elder sister's age = 35 years

Younger sister age = x-10= 35-10 = 25 years

Answer 2

Answer:

elder one 35 younger one 10_35-10=25

Step-by-step explanation:

×15=2(×-25) × 15= 2×50 ×=35