Question

13. The digit in tens place of a two digit number is 4 times the digit in one's place. If you
interchange the digits of this two digit number and add the resulting number to the
original number, you get 55. What is the original number?
[Ans:41]​

Answer 1

Answer:

original number is 41

Step-by-step explanation:

let the digit in one's place = x

then digit of tens place = 4x

so. original number is formed 10(4x) + x =40x + x = 41x

and number obtained by interchanging the digit is 10x + 4x

= 14x

[10(4x) + x] + [10x + 4x] = 55

41x + 14x = 55

55x = 55

x = 55/55

x = 1

then original number is 10(4x) + x

= 10 × 4(1) + 1

= 40 + 1 = 41

Answer 2

Hope it helps :) ...