Question

13. The digit in the units place of a two-digit number is twice the digit in its tens place. The quotient obtained when the number is divided by the sum of its digits is 4. Find the number.
(behind it shows 48 is answer but idk how, so can anyone show me pls) ​

Answer 1

Answer:

42

Step-by-step explanation:

Let 10y+x be the digit number.

It is given that the ten's place is twice the digit at unit's

place.

i.e. y=2x  ------(1)

Also,  (10y+x)+(10x+y)=66

10y+x+10x+y=66

11y+11x=66

⇒x+y=6

⇒x+2x=6  [from (1)]

⇒3x=6

⇒x=2

Form (1), y=2(2)=4

The required number =10(4)+2=42

Hope this will help you !

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