Question

13) The displacement of a simple harmonic
oscillator is
y = 5 sin( pie t /3)m. Then its
velocity
at t=1s​

Answer 1

Answer:

ANSWER

The displacement of particle, executing SHM is

y=5sin4t+3π......(i)

Velocity of particle

dtdy=dt5dsin4t+3π

=5cos4t+3π

=20cos4t+3π

Velocity at  t=4T

dtdyt=4T=20cos4×4T+3π

Or u=20cosT+3π.......(ii)

Now, putting value of T in eQ.  (II), WE GET

U=20cos2π+3π

=−20sin3π

=−20

Explanation:

The displacement of particle, executing SHM is

y=5sin4t+3π......(i)

Velocity of particle

dtdy=dt5dsin4t+3π

=5cos4t+3π

=20cos4t+3π

Velocity at  t=4T

dtdyt=4T=20cos4×4T+3π

Or u=20cosT+3π.......(ii)

Now, putting value of T in eQ.  (II), WE GET

U=20cos2π+3π

=−20sin3π

=−20×