13) The factorization of ab-a-b+1 is
a) (a-1)(b-1)
b)(a+1)(b+1)
c)(a-1)(b+1)
d)(a+1)(b-1)
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Answer:
ab-a-b+1
a(b-1) -b(b-1)
(b-1)is common and get out
(b-1) {a-1}
(b-1)(a-1)
Step-by-step explanation:
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