Question

13) The factorization of ab-a-b+1 is
a) (a-1)(b-1)
b)(a+1)(b+1)
c)(a-1)(b+1)
d)(a+1)(b-1)​

Answer 1

Answer:

ab-a-b+1

a(b-1) -b(b-1)

(b-1)is common and get out

(b-1) {a-1}

(b-1)(a-1)

Step-by-step explanation: